合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

        COMP9312代做、Java/c++編程設計代寫

        時間:2024-07-30  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



        The University of New South Wales - COMP9312 - 24T2 - Data
        Analytics for Graphs
        Assignment 2
        Distributed Graph Processing, Feature Engineering,
        and Graph Neural Networks
        Important updates:
        Update @ 25 Jul 2024
        Fix the error or the weight matrix W and make the GAT layer
        formulation clearer in Q2.1.
        Summary
        Submission Submit an electronic copy of all answers on Moodle
        (Only the last submission will be used).
        Required
        Files
        A .pdf file is accepted. The file name should be
        ass2_zid.pdf
        Deadline 9 pm Friday 2 August (Sydney Time)
        Marks 20 marks (10% toward your total marks for this
        course)
        Late penalty. 5% of max assessment marks will be deducted for each
        additional day (24 hours) after the specified submission time and date.
        No submission is accepted 5 days (120 hours) after the deadline.
        START OF QUESTIONS
        Q1 (3 marks)
        2024/7/25 11:34 COMP9312 24T2 Assignment 2
        https://cgi.cse.unsw.edu.au/~cs9312/24T2/assignment/ass2/ 1/5
        Figure 1
        Figure 2 Figure 3
        1.1 Are the graphs in Figure 1 and Figure 2 homomorphic? If so,
        demonstrate a matching instance. (1 mark)
        1.2 Present all unique subgraphs in Figure 1 that are isomorphic to the
        graph in Figure 3. For example, { }, {
        }, and { } are all considered as
        the same subgraph 123. (2 marks)
        Marking for Q1.1: 1 mark is given for the correct answer. 0 mark is
        given for all other cases.
        Marking for Q1.2: 2 marks are given if the result subgraphs are
        correct, complete, and not redundant. Extra subgraphs and missing
        subgraphs will result in a loss of marks.
        Q2 (5 marks)
        2.1 Given an undirected graph as shown in Figure 4,
        Figure 4
        we aim to compute the output of the first graph convolutional layer
        with self-loops using the Graph Attention Network (GAT) model. The
        goal is to transform the initial node embeddings from a dimension of 4
        to a dimension of 5 through this layer. The equation can be written as:
        v1 : 1, v2 : 2, v3 : 3
        v1 : 2, v2 : 1, v3 : 3 v1 : 3, v2 : 1, v3 : 2
        H 1
        2024/7/25 11:34 COMP9312 24T2 Assignment 2
        https://cgi.cse.unsw.edu.au/~cs9312/24T2/assignment/ass2/ 2/5
        where indicates the -dimensional embedding of node in layer ,
        and . is the
        weighting factor of node 's message to node .
        denotes the weight matrix for the neighbours of in layer , denotes
        the dimension of the node embedding in layer . denotes the
        non-linear function. The initial embedding for all nodes is
        stacked in . is the weight matrices. Self-loops are included in
        the calculation to ensure that the node's information is retained.
        Therefore, the term is added to its set of neighbors, which can be
        expressed as . Round the values to 2 decimal places (for
        example, 3.333 will be rounded to 3.33 and 3.7571 will be rounded to
        3.76). (3 marks)
        2.2 Please determine whether the following statements are TRUE or
        FALSE. (2 marks)
        a. Skip-connections is a good technique used to alleviate over-
        smoothing.
        b. To design a model for predicting dropout on a course website, we
        represent it as a bipartite graph where nodes indicate students or
        courses. The task here is considered as node classification.
        c. Graph Attention Network (GAT) has less expressive power
        compared to GCN, as it computes the attention score between
        each pair of neighbors, which introduces extra computational
        complexity.
        d. The main difference between GraphSAGE and GCN is that
        GraphSAGE needs an activation function to add nonlinearity.
        Marking for Q2.1: 3 marks are given for the correct result. Incorrect
        values will result in a deduction of marks. Providing a detailed and
        correct description of the calculation will earn marks for a valid
        attempt, even if there are major mistakes in the result.
        Marking for Q2.2: 0.5 mark is given for each correct TRUE/FALSE
        answer.
        Q3 (8 marks)
        h(l)v =      
        u  N(v)  {v}
          vuW (l)h
        (l?1)
        hlv dl v l
        H l = [hlv1, h
        l
        v2, h
        l
        v3, h
        l
        v4, h
        l
        v5, h
        l
        v6]
        T avu = 1|N(v)  {v}|
        u v W (l)    Rdl?dl?1
        v l dl
        l   (?)
        ReLU
        H 0 W 1
        v
        {v}    N(v)
        H 0 =
        2024/7/25 11:34 COMP9312 24T2 Assignment 2
        https://cgi.cse.unsw.edu.au/~cs9312/24T2/assignment/ass2/ 3/5
        Figure 5
        Suppose we aim to count the number of shortest paths from a source
        vertex to all other vertices in an undirected unweighted graph shown
        using Pregel.
        3.1 Write the pseudocode for the compute implementation in Pregel. (3
        marks)
        3.2 Assume we run your algorithm with the source node 1 for the graph
        in Figure 5 on three workers. Vertices 1 and 5 are in worker X. Vertices
        2 and 4 are in worker Y. Vertices 3, 6 and 7 are in worker Z. Please
        indicate the set of active vertices and how many messages are sent in
        each iteration. (3 marks)
        3.3 Can the combiner optimization be used in this case? If yes, write
        the pseudocode for a combiner implementation. Calculate how many
        messages are sent in each iteration if the combiner is used in 3.2. If no,
        briefly discuss why a combiner cannot be used. (2 marks)
        Marking for Q3.1: 3 marks are given for the correct answer. 0 mark is
        given for all other cases.
        Marking for Q3.2: 2 marks are given for the correct answer. 0 mark is
        given for all other cases.
        Marking for Q3.3: 3 marks are given for the correct answer. 0 mark is
        given for all other cases.
        Q4 (4 marks)
        Consider the graph in Figure 6,
        2024/7/25 11:34 COMP9312 24T2 Assignment 2
        https://cgi.cse.unsw.edu.au/~cs9312/24T2/assignment/ass2/ 4/5
        Figure 6
        Figure 7
        4.1 Compute the betweenness centrality and closeness centrality of
        nodes C and H in Figure 6. Round the values to 2 decimal places (for
        example, 3.333 will be rounded to 3.33 and 3.7571 will be rounded to
        3.76). (2 marks)
        4.2 Given the graphlets in Figure 7, derive the graphlet degree vector
        (GDV) for nodes A and G. Note that only the induced matching
        instances are considered in GDV. (2 marks)
        Marking for Q4.1: 1 mark is given for correct betweenness centrality
        values. 1 mark is given for correct closeness centrality values.
        Marking for Q4.2: 1 mark is given for each correct vector. Incorrect
        values in each vector will result in a deduction of marks.
        END OF QUESTIONS
        2024/7/25 11:34 COMP9312 24T2 Assignment 2


        請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp


         

        掃一掃在手機打開當前頁
      1. 上一篇:代寫INFS1603、代做 c++/Java 程序語言
      2. 下一篇:代寫DDES9903、代做C/C++,Python設計編程
      3. 無相關信息
        合肥生活資訊

        合肥圖文信息
        急尋熱仿真分析?代做熱仿真服務+熱設計優化
        急尋熱仿真分析?代做熱仿真服務+熱設計優化
        出評 開團工具
        出評 開團工具
        挖掘機濾芯提升發動機性能
        挖掘機濾芯提升發動機性能
        海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
        海信羅馬假日洗衣機亮相AWE 復古美學與現代
        合肥機場巴士4號線
        合肥機場巴士4號線
        合肥機場巴士3號線
        合肥機場巴士3號線
        合肥機場巴士2號線
        合肥機場巴士2號線
        合肥機場巴士1號線
        合肥機場巴士1號線
      4. 短信驗證碼 酒店vi設計 deepseek 幣安下載 AI生圖 AI寫作 aippt AI生成PPT 阿里商辦

        關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

        Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
        ICP備06013414號-3 公安備 42010502001045

        主站蜘蛛池模板: 一区二区三区四区在线视频| 精品一区二区视频在线观看| 久久久久人妻精品一区三寸| 免费无码一区二区| 3d动漫精品啪啪一区二区中| 久久亚洲中文字幕精品一区| 午夜在线视频一区二区三区| 日韩免费无码一区二区三区| 国产在线aaa片一区二区99| 精品国产高清自在线一区二区三区 | 国产激情一区二区三区| 国产SUV精品一区二区88| 精品国产一区二区三区四区 | 亚洲国产精品一区二区成人片国内| 日韩精品久久一区二区三区| 日本无卡码一区二区三区| 91大神在线精品视频一区| 日韩欧国产精品一区综合无码| 中文字幕精品亚洲无线码一区应用| 日韩一区二区三区在线精品| 国产在线一区二区视频| 风间由美在线亚洲一区| 免费看AV毛片一区二区三区| 精品国产一区二区三区香蕉事| 人妻视频一区二区三区免费| 无码日本电影一区二区网站 | 一区二区福利视频| 日本一区二区三区精品国产 | 激情无码亚洲一区二区三区| 亚洲中文字幕一区精品自拍| 无码中文字幕一区二区三区| 国模视频一区二区| 日本免费精品一区二区三区| 亚洲一区二区精品视频| 伦理一区二区三区| 少妇特黄A一区二区三区| 中文字幕av一区| 国产一区二区三区电影| 久久综合精品国产一区二区三区| 国产在线观看一区二区三区精品| 精品国产一区二区三区免费|