99爱在线视频这里只有精品_窝窝午夜看片成人精品_日韩精品久久久毛片一区二区_亚洲一区二区久久

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代寫 MATH5905、代做 Python/java 程序
代寫 MATH5905、代做 Python/java 程序

時間:2025-03-17  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



MATH5905 Term One 2025 Assignment One Statistical Inference University of New South Wales School of Mathematics and Statistics MATH5905 Statistical Inference Term One 2025 Assignment One Given: Friday 28 February 2025 Due date: Sunday 16 March 2025 Instructions: This assignment is to be completed collaboratively by a group of at most 3 students. Every effort should be made to join or initiate a group. (Only in a case that you were unable to join a group you can present it as an individual assignment.) The same mark will be awarded to each student within the group, unless I have good reasons to believe that a group member did not contribute appropriately. This assignment must be submitted no later than 11:59 pm on Sunday, 16 March 2025. The first page of the submitted PDF should be this page. Only one of the group members should submit the PDF file on Moodle, with the names, student numbers and signatures of the other students in the group clearly indicated on this cover page. By signing this page you declare that: I/We declare that this assessment item is my/our own work, except where acknowledged, and has not been submitted for academic credit elsewhere. I/We acknowledge that the assessor of this item may, for the purpose of assessing this item reproduce this assessment item and provide a copy to another member of the University; and/or communicate a copy of this assessment item to a plagiarism checking service (which may then retain a copy of the assessment item on its database for the purpose of future plagiarism checking). I/We certify that I/We have read and understood the University Rules in respect of Student Academic Misconduct. Name Student No. Signature Date 1 MATH5905 Term One 2025 Assignment One Statistical Inference Problem One a) Suppose that the X and Y are two components of a continuous random vector with a density fX,Y (x, y) = 12xy 3, 0 < x < y, 0 < y < c (and zero else). Here c is unknown. i) Find c. ii) Find the marginal density fX(x) and FX(x). iii) Find the marginal density fY (y) and FY (y). iv) Find the conditional density fY |X(y|x). v) Find the conditional expected value a(x) = E(Y |X = x). Make sure that you show your working and do not forget to always specify the support of the respective distribution. b) In the zoom meeting problem from the lecture, show that the probability that if there are 40 participants in the meeting then the chance that two or more share the same birthday, is very close to 90 percent. Problem Two A certain river floods every year. Suppose that the low-water mark is set at 1 and the high- water mark X has a distribution function FX(x) = P (X ≒ x) = 1? 1 x3 , 1 ≒ x <﹢ 1. Verify that FX(x) is a cumulative distribution function 2. Find the density fX(x) (specify it on the whole real axis) 3. If the (same) low-water mark is reset at 0 and we use a unit of measurement that is 110 of that used previously, express the random variable Z for the new measurement as a function of X. Find the cumulative distribution function and the density of Z. Problem Three a) A machine learning model is trained to classify emails as spam or not spam based on certain features. The probability that an email is spam is 0.3. The probability that the model predicts spam given that the email is actually spam, is 0.9. The probability that the model predicts spam given that the email is not spam, is 0.15. If a randomly received email is classified as spam by the model, what is the probability that the email is actually spam? b) In a Bayesian estimation problem, we sample n i.i.d. observations X = (X1, X2, . . . , Xn) from a population with conditional distribution of each single observation being the geometric distribution fX1|成(x|牟) = 牟x(1? 牟), x = 0, 1, 2, . . . ; 0 < 牟 < 1. The parameter 牟 is considered as random in the interval 成 = (0, 1) and is interpreted as a probability of success in a success-failure experiment. i) Interpret in words the conditional distribution of the random variable X1 given 成 = 牟. 2 MATH5905 Term One 2025 Assignment One Statistical Inference ii) If the prior on 成 is given by 而(牟) = 30牟4(1 ? 牟), 0 < 牟 < 1, show that the posterior distribution h(牟|X = (x1, x2, . . . , xn)) is also in the Beta family. Hence determine the Bayes estimator of 牟 with respect to quadratic loss. Hint: For 汐 > 0 and 汕 > 0 the beta function B(汐, 汕) = ÷ 1 0 x 汐?1(1 ? x)汕?1dx satisfies B(汐, 汕) = 忙(汐)忙(汕)忙(汐+汕) where 忙(汐) = ÷﹢ 0 exp(?x)x汐?1dx. A Beta (汐, 汕) distributed random vari- able X has a density f(x) = 1B(汐,汕)x 汐?1(1? x)汕?1, 0 < x < 1, with E(X) = 汐/(汐+ 汕). iii) Seven observations form this distribution were obtained: 2, 3, 5, 3, 5, 4, 2. Using zero-one loss, what is your decision when testing H0 : 牟 ≒ 0.80 against H1 : 牟 > 0.80. (You may use the integrate function in R or any favourite programming package to answer the question.) Problem Four A manager of a large fund has to make a decision about investing or not investing in certain company stock based on its potential long-term profitability. He uses two independent advi- sory teams with teams of experts. Each team should provide him with an opinion about the profitability. The random outcome X represents the number of teams recommending investing in the stock to their belief (based on their belief in its profitability). If the investment is not made and the stock is not profitable, or when the investment is made and the stock turns out profitable, nothing is lost. In the manager*s own judgement, if the stock turns out to be not profitable and decision is made to invest in it, the loss is equal to four times the cost of not investing when the stock turns out profitable. The two independent expert teams have a history of forecasting the profitability as follows. If a stock is profitable, each team will independently forecast profitability with probability 5/6 (and no profitability with 1/6). On the other hand, if the stock is not profitable, then each team predicts profitability with probability 1/2. The fund manager will listen to both teams and then make his decisions based on the random outcome X. a) There are two possible actions in the action space A = {a0, a1} where action a0 is to invest and action a1 is not to invest. There are two states of nature 成 = {牟0, 牟1} where 牟0 = 0 represents ※profitable stock§ and 牟1 = 1 represents ※stock not profitable§. Define the appropriate loss function L(牟, a) for this problem. b) Compute the probability mass function (pmf) for X under both states of nature. c) The complete list of all the non-randomized decisions rules D based on x is given by: d1 d2 d3 d4 d5 d6 d7 d8 x = 0 a0 a1 a0 a1 a0 a1 a0 a1 x = 1 a0 a0 a1 a1 a0 a0 a1 a1 x = 2 a0 a0 a0 a0 a1 a1 a1 a1 For the set of non-randomized decision rules D compute the corresponding risk points. d) Find the minimax rule(s) among the non-randomized rules in D. e) Sketch the risk set of all randomized rules D generated by the set of rules in D. You might want to use R (or your favorite programming language) to make the sketch precise. 3 MATH5905 Term One 2025 Assignment One Statistical Inference f) Suppose there are two decisions rules d and d∩. The decision d strictly dominates d∩ if R(牟, d) ≒ R(牟, d∩) for all values of 牟 and R(牟, d) < (牟, d∩) for at least one value 牟. Hence, given a choice between d and d∩ we would always prefer to use d. Any decision rule that is strictly dominated by another decisions rule is said to be inadmissible. Correspondingly, if a decision rule d is not strictly dominated by any other decision rule then it is admissible. Indicate on the risk plot the set of randomized decisions rules that correspond to the fund manager*s admissible decision rules. g) Find the risk point of the minimax rule in the set of randomized decision rules D and determine its minimax risk. Compare the two minimax risks of the minimax decision rule in D and in D. Comment. h) Define the minimax rule in the set D in terms of rules in D. i) For which prior on {牟1, 牟2} is the minimax rule in the set D also a Bayes rule? j) Prior to listening to the two teams, the fund manager believes that the stock will be profitable with probability 1/2. Find the Bayes rule and the Bayes risk with respect to his prior. k) For a small positive ? = 0.1, illustrate on the risk set the risk points of all rules which are ?-minimax. Problem Five The length of life T of a computer chip is a continuous non-negative random variable T with a finite expected value E(T ). The survival function is defined as S(t) = P (T > t). a) Prove that for the expected value it holds: E(T ) = ÷﹢ 0 S(t)dt. b) The hazard function hT (t) associated with T . (In other words, hT (t) describes the rate of change of the probability that the chip survives a little past time t given that it survives to time t.) i) Denoting by FT (t) and fT (t) the cdf and the density of T respectively, show that hT (t) = fT (t) 1? FT (t) = ? d dt log(1? FT (t)) = ? d dt log(S(t)). ii) Prove that S(t) = e? ÷ t 0 hT (x)dx. iii) Verify that the hazard function is a constant when T is exponentially distributed, i.e., 

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp

掃一掃在手機打開當前頁
  • 上一篇:代做MATH2110、代寫c/c++,Python程序
  • 下一篇:代寫 COMP3411、代做 C++編程語言
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
  • 短信驗證碼 trae 豆包網頁版入口 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    99爱在线视频这里只有精品_窝窝午夜看片成人精品_日韩精品久久久毛片一区二区_亚洲一区二区久久

          9000px;">

                美腿丝袜亚洲色图| 日韩成人一区二区三区在线观看| 欧美福利视频导航| 久久精品免费在线观看| 成人国产精品免费观看视频| 国产精品国产三级国产普通话蜜臀| 91色视频在线| 91色乱码一区二区三区| 国内精品视频一区二区三区八戒| 国产精品美女一区二区三区 | 日韩电影网1区2区| 综合色中文字幕| 国产精品你懂的在线| 日韩欧美成人激情| 91麻豆精品国产91久久久使用方法 | 免费成人av在线播放| 一区二区三区在线看| 国产精品网站在线观看| wwwwww.欧美系列| 欧美一区二区三区日韩| 7777精品伊人久久久大香线蕉完整版| 成人性视频网站| 精品无人码麻豆乱码1区2区 | 91丨porny丨首页| 91免费版在线看| 欧美日韩一区二区三区在线| 7777精品伊人久久久大香线蕉的| www日韩大片| 丝袜亚洲另类欧美综合| av中文字幕亚洲| 日韩午夜三级在线| 一区二区三区影院| 国产成人av一区二区三区在线| 日本精品视频一区二区三区| 欧美电影精品一区二区| 一区二区三区小说| 国产999精品久久| 欧美mv日韩mv国产网站app| 亚洲一二三四区不卡| 成人不卡免费av| 国产亚洲一区二区三区四区 | 伊人性伊人情综合网| 免费在线观看视频一区| 欧美日本一区二区| 一个色在线综合| 欧美日韩综合不卡| 全国精品久久少妇| 日韩一卡二卡三卡四卡| 裸体健美xxxx欧美裸体表演| 911精品国产一区二区在线| 国产婷婷色一区二区三区在线| 欧美一a一片一级一片| 国产精品99久久久| 久色婷婷小香蕉久久| 日韩一区中文字幕| 久久伊人中文字幕| 日韩精品一区二区三区四区 | 日韩欧美不卡在线观看视频| 91啪亚洲精品| 欧美剧在线免费观看网站 | 一区二区高清免费观看影视大全 | 蜜臀精品一区二区三区在线观看| 国产一区欧美一区| 美国一区二区三区在线播放| 午夜精品在线看| 亚洲一区在线观看视频| 亚洲私人影院在线观看| 亚洲伦在线观看| 亚洲综合男人的天堂| 五月天久久比比资源色| 麻豆91在线播放| 国产精品影音先锋| 国产**成人网毛片九色| 中文字幕高清一区| 日本久久电影网| 亚洲激情图片qvod| 成人免费高清视频在线观看| 久久精品久久综合| 欧美日韩一级视频| 久久精品国产精品青草| 91福利视频久久久久| 国产日韩欧美综合在线| 国产乱码精品一区二区三区忘忧草| 欧美人与性动xxxx| 亚洲成人激情综合网| 色94色欧美sute亚洲线路一久 | 色婷婷av一区二区三区之一色屋| 久久精品亚洲乱码伦伦中文| 老汉av免费一区二区三区| 欧美日韩精品一区视频| 亚洲国产精品影院| 色综合久久久久综合体| 一区在线播放视频| 9i看片成人免费高清| 国产精品乱码一区二区三区软件 | 欧美三级在线看| 亚洲成人久久影院| 宅男在线国产精品| 精品一区二区在线视频| 久久精品水蜜桃av综合天堂| 国产电影一区二区三区| 国产精品麻豆网站| 在线观看日韩高清av| 日韩国产欧美在线播放| 精品人在线二区三区| 国产伦精品一区二区三区免费迷 | 欧美日韩高清一区二区不卡| 美女久久久精品| 亚洲精品一区在线观看| 国产91丝袜在线播放九色| **网站欧美大片在线观看| 在线中文字幕一区| 日韩经典中文字幕一区| 久久久久久久久久久电影| 91玉足脚交白嫩脚丫在线播放| 亚洲国产另类av| 久久久美女毛片| 色哟哟亚洲精品| 青青草精品视频| 国产精品色婷婷| 欧美日韩国产综合久久| 国产成人综合在线| 午夜影院在线观看欧美| 国产欧美精品一区aⅴ影院| 欧美日韩国产精品成人| 国产99久久久久久免费看农村| 成人免费黄色在线| 国产成人免费xxxxxxxx| 国产1区2区3区精品美女| 粉嫩一区二区三区性色av| 91年精品国产| 日韩午夜激情免费电影| 国产精品久久久久三级| 免费在线观看视频一区| 国产一区二区三区最好精华液| 国产不卡免费视频| 91精品国产综合久久精品app| 日韩三级在线免费观看| 亚洲图片你懂的| 国产精品 日产精品 欧美精品| 99精品欧美一区二区蜜桃免费 | 国产乱人伦偷精品视频不卡 | 日韩高清中文字幕一区| 亚洲少妇最新在线视频| 丁香亚洲综合激情啪啪综合| 国产午夜精品在线观看| 欧美精品一区二区三区蜜桃| 久久亚洲春色中文字幕久久久| 色哟哟一区二区| 国产一区二区在线免费观看| 亚洲一区二区五区| 亚洲人快播电影网| 国产精品女人毛片| 久久久久免费观看| 欧美一区午夜精品| 欧美男女性生活在线直播观看| 91在线精品秘密一区二区| 成人成人成人在线视频| 石原莉奈一区二区三区在线观看| 欧美日韩不卡视频| 一区二区三区中文免费| 欧美一级理论片| 国产剧情一区二区三区| av激情亚洲男人天堂| 中文字幕一区二区三区av| 欧美色倩网站大全免费| 夜夜亚洲天天久久| 91成人在线免费观看| 丁香亚洲综合激情啪啪综合| fc2成人免费人成在线观看播放| 欧美在线观看一区| 亚洲三级电影全部在线观看高清| 国产亚洲欧洲997久久综合 | 亚洲网友自拍偷拍| 中文字幕一区二区三区视频| 久久久美女艺术照精彩视频福利播放| 国产日韩精品视频一区| 国产精品女主播在线观看| 亚洲少妇30p| 亚洲国产精品一区二区www在线| 亚洲成人免费影院| 毛片av中文字幕一区二区| 麻豆国产一区二区| 国产成人免费9x9x人网站视频| 国产福利一区二区三区在线视频| 成人午夜在线播放| 91免费精品国自产拍在线不卡| 在线观看一区二区视频| 欧美人动与zoxxxx乱| 日韩免费一区二区| 国产欧美一区二区在线观看| 国产精品国产a| 亚洲午夜久久久久中文字幕久| 偷拍亚洲欧洲综合| 国产白丝精品91爽爽久久| 91国偷自产一区二区三区成为亚洲经典 | 久久久精品2019中文字幕之3| 国产精品美女www爽爽爽| 亚洲一区二区三区四区五区黄| 另类调教123区|